Print Given Money or Value in Words

#include<stdio.h>

int main()

{

 int i,j,k=0,value,count,a[10],dummy;

 char *ones[]={"zero","one","two","three","four","five","six","seven","eight","nine"};

 char *temp[]={"ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"};

 char *tens[]={"-","-","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"};

 //hundreds are same as ones

 printf("Enter Value upto 6 digits to get in Words\n");

 dummy=value;

 scanf("%d",&value);

 while(value>0)

 {

  i=value%10;

  a[k]=i;

  k++;

  value/=10;

 }

 //Here if 12345 is given then a[0]=5,a[1]=4 and soon then last but one digit will be at a[1]

 int totalDigits=k-1;

 if(totalDigits<6)

   {

     for(i=totalDigits;i>=0;i--)

     {

      if(i==5 && a[i]!=0)

      {

      printf("%s lakh ",ones[a[i]]);

      }

      if(i==4 || i==3)

      {

       //Start

       if(i==4 && a[i]==0)

       {

        printf("%s thousand ",ones[a[i-1]]);

        i--;

       }

       else if(i==4 && a[i]==1)

       {

        printf("%s thousand ",temp[a[i-1]]);

        i--;

       }

       else if(i==4)

       {

        printf("%s ",tens[a[i]]);

       }

       else

       {

        printf("%s thousand ",ones[a[i]]);

       }

          //end

      }

      if(i==2 && a[i]!=0)

      {

          printf("%s hundred and ",ones[a[i]]);

      }

      if(i==2 && a[i]==0)

      {

       printf("and ");

      }

      if(i==1 || i==0)

      {

       if(i==1 && a[i]==0)

       {

        printf("%s only\n",ones[a[i-1]]);

        i--;

        break;

       }

          if(i==1 && a[i]==1)

       {

        printf("%s only\n",temp[a[i-1]]);

        i--;

        break;

       }

          if(i==1 && a[i]!=1 && a[i]!=0)

       {

        printf("%s ",tens[a[i]]);

       }

       if(i==0 && a[i]!=0)

       {

        printf("%s only\n",ones[a[i]]);

       }

      }

     }

   }

   else

   {

    printf("Enter only upto 6 digits\n");

   }

return 0;

}

Number of Characters need to make a String Palindrome

#include<stdio.h>

#include<string.h>

int main(){

   

    int i=0,j,totChar=0,flag=0,c;

    char str[100];

    printf("Enter a String\n");

    scanf("%s",str);

    int len=strlen(str);

    j=len-1;

   

    while(i<j)

    {

           if(str[i]==str[j])

           {

               i++;

               j--;

              flag=1;

           }

        else

        {

            totChar++;

            i++;

            flag=0;

        }

    }

    if(flag!=1)

    totChar=len-1;

    c=totChar-1;

    printf("Total Characters required=%d\n",totChar);

   

    for(i=0;i<totChar;i++)

        str[len+i]=str[c--];

    str[len+i]='\0';

    printf("Final String of Palindrome=%s\n",str);

    return 0;

}

Input    : mada

Output : Total Characters required =1

               Final String of Palindrome = madam